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Proof step 1 from proof minmax (conclusion)
⊦ s.butmin = ∅ ∧ s ≠ ∅ → s.butmax = ∅
System applied rule normalize
And obtained the following new goals
Proof step 2
:
s.butmin = ∅ ⊦ s.butmax = ∅, s = ∅
Rule argument
Additional information