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Proof step 1 from proof size-lsleq (conclusion)
⊦ a < b ∧ ¬ b ∈ s → #(s ++ a ++ b) = #(s ++ a) + 1
System applied rule normalize
And obtained the following new goals
Proof step 2
:
a < b ⊦ #(s ++ a ++ b) = #(s ++ a) + 1, b ∈ s
Rule argument
Additional information