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Proof step 11 from proof butmin-rewput (previous step)

st.min < st[a, d].min, st[a, d].min ∈ st ⊦ st[a, d].min = st.min, a = st[a, d].min

Heuristic weak cut applied rule cut formula

And obtained the following new goals

Proof step 12:
st.min < st[a, d].min, st[a, d].min ∈ st ⊦ st[a, d].min = st.min, a = st[a, d].min, st = ∅

Rule argument

fma: st = ∅

Additional information

Used simplifier rules: min: ⊦ (∅)[a, d].min = a; Used formulas: st = ∅