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Proof step 6 from proof empty-01 (previous step)

st.keys = ∅, st.min ∈ st ⊦ ¬ a ∈ st ∧ st[a] = (∅)[a]

Heuristic weak cut applied rule cut formula

And obtained the following new goals

Proof step 7:
st.keys = ∅, st.min ∈ st ⊦ st = ∅, ¬ a ∈ st ∧ st[a] = (∅)[a]

Rule argument

fma: st = ∅

Additional information

Used simplifier rules: empty: ⊦ ∅.keys = ∅;% ⊦ ¬ a ∈ ∅; (s) Used formulas: st = ∅