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Proof step 1 from proof neq (conclusion)

⊦ st[a, d].keys = st.keys ↔ a ∈ st

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: insert-03: ⊦ st[a, d].keys = st.keys ++ a;%Keys: ⊦ a ∈ st.keys ↔ a ∈ st;% ⊦ s ++ a = s ↔ a ∈ s; (s)