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Proof step 2 from proof size-del-02 (previous step)

a ∈ st, # st.keys ≤ # (st -- a).keys ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
a ∈ st, # st.keys ≤ # (st -- a).keys ⊦ a < st.min

Rule argument

Additional information

Used simplifier rules: Min-min: ⊦ a ∈ st → ¬ a < st.min;%inf: ⊦ a ∈ st → a ∈ st.keys;%Keys: ⊦ a ∈ st.keys ↔ a ∈ st;