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Proof step 5 from proof size-del-02 (previous step)

a ∈ st, a ∈ st.keys, # st.keys ≤ #(st.keys -- a) ⊦ a < st.min

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
a ∈ st, # st.keys ≤ #(st.keys -- a) ⊦ a < st.min

Rule argument

Additional information

Used simplifier rules: Keys: ⊦ a ∈ st.keys ↔ a ∈ st;