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Proof step 29 from proof acyclic-rem-not-reachable (previous step)

ce.nxt = H[H[r0].nxt].nxt, path(r ' + x0 + r0 ' + (ce.nxt ' + x1) + H[r0].nxt ', H[r0, ce]), path(ce.nxt ' + x1 + H[r0].nxt ', H), reachable(r, r0, H), H[r0].nxt ∈ H, r0 ∈ H ⊦ H[r0].nxt = r0, H[r0].nxt = null, H[r0].nxt = ce.nxt, r = r0, r = H[r0].nxt, r = ce.nxt, r0 = null, r0 = ce.nxt, dups(x0 + x1), dups(x0), dups(x1), ce.nxt ∈ x0, ce.nxt ∈ x1, r0 ∈ x0, r ∈ x1, r ∈ x0, H[r0].nxt ∈ x1, H[r0].nxt ∈ x0, r0 ∈ x1, ∃ x. path(ce.nxt ' + x, H) ∧ (ce.nxt ' + x).last = H[r0].nxt

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

pos: right 20 terms: x1 + H[r0].nxt '

Additional information

Used simplifier rules: a: ⊦ (x0 + x1) + x2 = x0 + x1 + x2; from specification list[reflist]% ⊦ (r ' + x0 + r0 ').last = r0; (s) Used terms: x1 + H[r0].nxt '