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Proof step 4 from proof path-postfix (previous step)

path((r0 + x0) + r ' + y, H), ∀ r, y, H. path(x0 + r ' + y, H) → path(r ' + y, H) ⊦ path(r ' + y, H)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
path((r0 ' + x0) + r ' + y, H), ∀ r, y, H. path(x0 + r ' + y, H) → path(r ' + y, H) ⊦ path(r ' + y, H)

Rule argument

Additional information

Used simplifier rules: ⊦ r + x0 = r ' + x0; (s)