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Proof step 5 from proof reachable-addnew (
previous step
)
∃ x. path(r ' + x, H) ∧ (r ' + x).last = r1 ⊦ reachable(r, r1, H[r2, ce]), r2 ∈ H
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 6
:
path(r ' + x, H) ⊦ reachable(r, (r ' + x).last, H[r2, ce]), r2 ∈ H
Rule argument
Additional information