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Proof step 1 from proof reachable-split-last (conclusion)

⊦ r ≠ r0 → (reachable(r, r0, H) ↔ (∃ r1. reachable(r, r1, H) ∧ H[r1].nxt = r0 ∧ r0 ∈ H ∧ r0 ≠ null))

System applied rule normalize

And obtained the following new goals

Rule argument

Additional information