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Proof step 8 from proof reachnext (previous step)

H[r0].nxt ∈ H, r0 ∈ H ⊦ H[r0].nxt = null, r0 = null, ∃ x. path(r0 ' + x, H) ∧ (r0 ' + x).last = H[r0].nxt

User applied rule exists right

And closed the goal!

Rule argument

pos: right 3 terms: H[r0].nxt ' abort: F discard: T computed: F

Additional information

Used simplifier rules: path-two: ⊦ path(r ' + r0 ', H) ↔ r ∈ H ∧ r0 ∈ H ∧ r ≠ null ∧ r0 ≠ null ∧ H[r].nxt = r0;%a: ⊦ (x0 + x1) + x2 = x0 + x1 + x2; from specification list[reflist]% ⊦ (x0 + r ').last = r; (s) Used terms: H[r0].nxt '