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Proof step 20 from proof rtc+-unfold-last (previous step)

p(c, b), p*(a, c) ⊦ ∃ n. n ≠ 0 ∧ rtc(n, a, b)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 21:
⊦ p*(a, b) ↔ (∃ n. rtc(n, a, b))
Proof step 22:
p(c, b), ∃ n. rtc(n, a, c) ⊦ ∃ n. n ≠ 0 ∧ rtc(n, a, b)

Rule argument

spec: <toplevel> name: rtc seq: ⊦ p*(a, b) ↔ (∃ n. rtc(n, a, b)) subst: [b, a] → [c, a] flags: <all paths>

Additional information

Used terms: c, a