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Proof step 9 from proof rtc+-unfold-last (previous step)

p(a, c), rtc(n0, c, b), n0 = 0 ∨ p*(c, c0) ∧ p(c0, b) ⊦ ∃ c. p*(a, c) ∧ p(c, b)

User applied rule case distinction

And obtained the following new goals

Proof step 10:
n0 = 0, p(a, c), rtc(n0, c, b) ⊦ ∃ c. p*(a, c) ∧ p(c, b)
Proof step 12:
p(a, c), p(c0, b), p*(c, c0), rtc(n0, c, b) ⊦ ∃ c. p*(a, c) ∧ p(c, b)

Rule argument

pos: left 3

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