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Proof step 6 from proof rtc-trans (previous step)

Pelem ^*(b, c), rtc(n, Pelem)(a, b) ⊦ Pelem ^*(a, c)

User applied rule structural induction

And obtained the following new goals

Proof step 7:
Pelem ^*(b, c), rtc(n0 +1, Pelem)(a, b), ∀ Pelem, b, c, a. Pelem ^*(b, c) ∧ rtc(n0, Pelem)(a, b) → Pelem ^*(a, c) ⊦ Pelem ^*(a, c)

Rule argument

indvar: n

Additional information

Used simplifier rules: rtc-base: ⊦ rtc(0, Pelem)(a, b) ↔ a = b;%nat freely generated by 0, +1;;