[Imprint]
[Data Privacy Statement]
[E-Mail]
View
long theorem info
. View
the proof
. Back to
main index
. View
the specification
. View
theorem base summary
, View
theorem base listing
, the
used properties by spec
, the
dependency list
, the
symbol table
,
Proof step 8 from proof size-two-06 (
previous step
)
#(s0 ++ a0) < 2, a ∈ s0, ∀ a, b. # s0 < 2 ∧ a ∈ s0 ∧ b ∈ s0 → a = b, b = a0 ∨ b ∈ s0 ⊦ b = a
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 9
:
#(s0 ++ a0) < 2, a ∈ s0, ∀ a, b. # s0 < 2 ∧ a ∈ s0 ∧ b ∈ s0 → a = b, b = a0 ∨ b ∈ s0 ⊦ b = a
Rule argument
Additional information