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Proof step 5 from proof size-zero-02 (previous step)

#(s0 ++ a) = 0 ⊦ # s0 = 0, s0 = ∅

Heuristic cut applied rule cut formula

And closed the goal!

Rule argument

fma: a ∈ s0

Additional information

Used simplifier rules: eq: ⊦ a ∈ s → s ++ a = s;%Size-insert: ⊦ ¬ a ∈ s → #(s ++ a) = # s + 1;% ⊦ m + 1 ≠ 0; (s)%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic%c: ⊦ m + n = n + m; from specification nat-basic Used formulas: a ∈ s0