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Proof step 16 from proof intersection-size (previous step)

# s0 + # s1 < #(s0 ∩ s1), a0 ∈ s0, a ∈ s0, ∀ s0. ¬ # s0 + # s1 < #(s0 ∩ s1) ⊦ a ∈ s1

User applied rule all left

And closed the goal!

Rule argument

pos: left 4 terms: s0 abort: F discard: F computed: F

Additional information

Used terms: s0