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Proof step 4 from proof intersection-size (previous step)

# s0 + #(s1 ++ a) < #(s0 ∩ (s1 ++ a)), ∀ s0. ¬ # s0 + # s1 < #(s0 ∩ s1) ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
# s0 + #(s1 ++ a) < #(s0 ∩ (s1 ++ a)), ∀ s0. ¬ # s0 + # s1 < #(s0 ∩ s1) ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic