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Proof step 1 from proof uninsubdel (conclusion)
⊦ ¬ a ∈ s ∪ s0 ∧ s1 ⊆ s → ¬ a ∈ (s1 -- b) ∪ s0
System applied rule normalize
And obtained the following new goals
Proof step 2
:
a ∈ (s1 -- b) ∪ s0, s1 ⊆ s ⊦ a ∈ s ∪ s0
Rule argument
Additional information