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Proof step 1 from proof union-size-02 (conclusion)
⊦ ¬ a ∈ s ∧ a ∈ s0 → #(s ∪ s0) = #(s ∪ (s0 -- a)) + 1
System applied rule normalize
And obtained the following new goals
Proof step 2
:
a ∈ s0 ⊦ #(s ∪ s0) = #(s ∪ (s0 -- a)) + 1, a ∈ s
Rule argument
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