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Proof step 3 from proof union-size-ls-in (previous step)

a ∈ s0, a ∈ s1, a0 ∈ s0, a1 ∈ s1, # s0 + # s1 ≤ #(s0 ∪ s1) ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ #(s0 ∪ s1) = # s0 + # s1 - #(s0 ∩ s1)
Proof step 5:
a1 ∈ s1, a0 ∈ s0, a ∈ s1, a ∈ s0, # s0 + # s1 ≤ # s0 + # s1 - #(s0 ∩ s1) ⊦

Rule argument

spec: <toplevel> name: union-size-03 seq: ⊦ #(s0 ∪ s1) = # s0 + # s1 - #(s0 ∩ s1) subst: [s1, s0] → [s1, s0] flags: <all paths>

Additional information

Used terms: s1, s0