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Proof step 2 from proof union-size-not-less (previous step)

# s0 + # s1 < #(s0 ∪ s1) ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
# s0 + # s1 < #(s0 ∪ s1) ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic