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Proof step 1 from proof unsubdel-01 (conclusion)

⊦ s ⊆ s0 ∧ ¬ a ∈ s → (s0 -- a) ∪ s = s0 -- a

System applied rule normalize

And obtained the following new goals

Proof step 2:
s ⊆ s0 ⊦ (s0 -- a) ∪ s = s0 -- a, a ∈ s

Rule argument

Additional information