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Proof step 2 from proof Data-in-putsame (previous step)

⊦ ∃ a0. a0 ∈ st[a, d] ∧ st[a, d][a0] = d

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

pos: right 1 terms: a

Additional information

Used simplifier rules: ⊦ a ∈ st[a, d]; (s)% ⊦ st[a, d][a] = d; (s) Used terms: a