[Imprint][Data Privacy Statement][E-Mail]

View long theorem info. View the proof. Back to main index. View the specification. View theorem base summary, View theorem base listing, the used properties by spec, the dependency list, the symbol table,

Proof step 1 from proof dom-union-l (conclusion)

⊦ dom(st0 ⊕ st1) = dom st0 ∪ dom st1

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ s1 = s2 ↔ (∀ a. a ∈ s1 ↔ a ∈ s2)
Proof step 3:
⊦ ∀ a. a ∈ dom(st0 ⊕ st1) ↔ a ∈ dom st0 ∪ dom st1

Rule argument

spec: set-basic name: Extension seq: ⊦ s1 = s2 ↔ (∀ a. a ∈ s1 ↔ a ∈ s2) subst: [s2, s1] → [dom st0 ∪ dom st1, dom(st0 ⊕ st1)] flags: <all paths>

Additional information

Used terms: dom st0 ∪ dom st1, dom(st0 ⊕ st1)