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Proof step 3 from proof size-subset (previous step)

st ⊆ st0, ∀ st1, st. # st1 < # st0 → st ⊆ st1 → # st ≤ # st1 ⊦ # st ≤ # st0

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: subset-size: ⊦ # st0 < # st → ¬ st ⊆ st0;% ⊦ m ≤ n ↔ ¬ n < m; (ss)