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Proof step 2 from proof subset-size (previous step)

# st0 < # st, st ⊆ st0 ⊦

User applied rule structural induction

And obtained the following new goals

Proof step 3:
# st0 < # st1[a, d], st1[a, d] ⊆ st0, ∀ st0. ¬(# st0 < # st1 ∧ st1 ⊆ st0) ⊦

Rule argument

indvar: st

Additional information

Used simplifier rules: gen: ⊦ ;%subset-empty: ⊦ ∅ ⊆ st;%Size-empty: ⊦ # ∅ = 0;% ⊦ ¬ n < 0; (s)