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Proof step 4 from proof subset-size (previous step)

# st0 < # st1[a, d], st1[a, d] ⊆ st0, ∀ st. ¬ # st < # st1 ∨ ¬ st1 ⊆ st ⊦ st1[a, d] = ∅

Heuristic weak cut applied rule cut formula

And obtained the following new goals

Proof step 5:
# st0 < # st1[a, d], a ∈ st1, st1[a, d] ⊆ st0, ∀ st. ¬ # st < # st1 ∨ ¬ st1 ⊆ st ⊦ st1[a, d] = ∅
Proof step 18:
# st0 < # st1[a, d], st1[a, d] ⊆ st0, ∀ st. ¬ # st < # st1 ∨ ¬ st1 ⊆ st ⊦ st1[a, d] = ∅, a ∈ st1

Rule argument

fma: a ∈ st1

Additional information

Used formulas: a ∈ st1