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Proof step 8 from proof subset-size (previous step)

# st0 < # st1, a ∈ st1, st1[a, d] ⊆ st0, ∀ st. ¬ # st < # st1 ∨ ¬ st1 ⊆ st ⊦ st1[a, d] = ∅, st1 = ∅, st1[a] = d ∧ a ∈ st1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information