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Proof step 12 from proof append-cancel-l (previous step)

(λ n. (n < # x ⊃ x[n];nf(n - # x))) = (λ n. (n < # x ⊃ x[n];nf0(n - # x))) ⊦ nf(n) = nf0(n)

User applied rule expand left

And closed the goal!

Rule argument

pos: left 1 terms: n + # x abort: F discard: F computed: F

Additional information

Used simplifier rules: ⊦ ¬ m + n < m; (s)%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic%c: ⊦ m + n = n + m; from specification nat-basic% ⊦ m + n - m = n; (s) Used terms: n + # x