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Proof step 5 from proof append-cancel-l (previous step)

⌜x⌝ + ⌜nf⌝ = ⌜x⌝ + ⌜nf0⌝ ⊦ ⌜nf⌝ = ⌜nf0⌝

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
⌜x⌝ + ⌜nf⌝ = ⌜x⌝ + ⌜nf0⌝ ⊦ nf = nf0

Rule argument

Additional information

Used simplifier rules: ⊦ ⌜nf⌝ = ⌜nf0⌝ ↔ nf = nf0; (s)