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Proof step 1 from proof append-empty-01 (conclusion)

⊦ σ0 + σ1 = [] ↔ σ0 = [] ∧ σ1 = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
σ0 + σ1 = [] ⊦ σ0 = [] ∧ σ1 = []

Rule argument

Additional information

Used simplifier rules: append-empty: ⊦ σ + [] = σ;%append-assoc: ⊦ (σ + σ1) + σ2 = σ + σ1 + σ2;