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Proof step 10 from proof append-split (previous step)

# x = # x0, ⌜x⌝ + ⌜nf0⌝ = ⌜x0⌝ + ⌜nf⌝ ⊦ x = x0 ∧ ⌜nf0⌝ = ⌜nf⌝

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
# x = # x0, ⌜x⌝ + ⌜nf0⌝ = ⌜x0⌝ + ⌜nf⌝ ⊦ x = x0 ∧ nf0 = nf

Rule argument

Additional information

Used simplifier rules: ⊦ ⌜nf⌝ = ⌜nf0⌝ ↔ nf = nf0; (s)