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Proof step 6 from proof append-split (previous step)

⌜x⌝ + σ0 = ⌜x0⌝ + σ2, ⌜# x⌝ = # ⌜x0⌝ ⊦ ⌜x⌝ = ⌜x0⌝ ∧ σ0 = σ2

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
# x = # x0, ⌜x⌝ + σ0 = ⌜x0⌝ + σ2 ⊦ x = x0 ∧ σ0 = σ2

Rule argument

Additional information

Used simplifier rules: size-fin: ⊦ # ⌜x⌝ = ⌜# x⌝ ;% ⊦ ⌜x⌝ = ⌜x0⌝ ↔ x = x0; (s)% ⊦ ⌜m⌝ = ⌜m0⌝ ↔ m = m0; (s)