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Proof step 2 from proof append-to-gr (previous step)

# x < n ⊦ x + y to n = x + (y to (n - # x))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
# x < n ⊦ x + y to n = x + (y to (n - # x))

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic