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Proof step 15 from proof elim-fromto (previous step)

σ1 = ⌜x0⌝ , ⌜nf⌝ = ⌜x⌝ + σ1 ⊦ x = nf to # x ∧ σ1 = ⌜nf from # x⌝

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: neq-fin-inf-03: ⊦ σ0 + ⌜x⌝ = ⌜nf0⌝ ↔ σ0 = ⌜nf0⌝ ;%append-assoc: ⊦ (σ + σ1) + σ2 = σ + σ1 + σ2;% ⊦ ⌜x⌝ ≠ ⌜nf⌝ ; (s)