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Proof step 16 from proof elim-fromto (previous step)

σ1 = ⌜nf0⌝ , ⌜nf⌝ = ⌜x⌝ + σ1 ⊦ x = nf to # x ∧ σ1 = ⌜nf from # x⌝

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 17:
⌜nf⌝ = ⌜x⌝ + ⌜nf0⌝ ⊦ x = nf to # x ∧ nf0 = nf from # x

Rule argument

Additional information

Used simplifier rules: ⊦ ⌜nf⌝ = ⌜nf0⌝ ↔ nf = nf0; (s)