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Proof step 19 from proof elim-fromto (previous step)

⌜nf⌝ = ⌜λ n. (n < # x ⊃ x[n];nf0(n - # x))⌝ ⊦ x = nf to # x ∧ nf0 = nf from # x

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 20:
⊦ x = (λ n. (n < # x ⊃ x[n];nf0(n - # x))) to # x ∧ nf0 = (λ n. (n < # x ⊃ x[n];nf0(n - # x))) from # x

Rule argument

Additional information

Used simplifier rules: ⊦ ⌜nf⌝ = ⌜nf0⌝ ↔ nf = nf0; (s)