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Proof step 25 from proof elim-fromto (previous step)

# σ0 = ⌜n⌝ , σ0 = ⌜nf0⌝ , ⌜nf⌝ = σ0 + σ1 ⊦ σ0 = ⌜nf to n⌝ ∧ σ1 = ⌜nf from n⌝

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: append-inf: ⊦ ⌜nf⌝ + σ = ⌜nf⌝ ;%append-assoc: ⊦ (σ + σ1) + σ2 = σ + σ1 + σ2;%size-inf: ⊦ # ⌜nf⌝ = ∞;% ⊦ ⌜m⌝ ≠ ∞; (s)% ⊦ ⌜nf⌝ = ⌜nf0⌝ ↔ nf = nf0; (s)