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Proof step 43 from proof from-append-add (previous step)

# x = n2 + n1, (n2 + n1) + n = # x0, x0[(n1 + n) + n0] = ((σ to n) + ⌜x⌝ )[(n1 + n) + n0], n0 < n2 ⊦ x0[(n1 + n) + n0] = x[n1 + n0], x = [], # σ < ⌜n⌝

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 44:
# x = n2 + n1, (n2 + n1) + n = # x0, x0[(n1 + n) + n0] = ((σ to n) + ⌜x⌝ )[(n1 + n) + n0], n0 < n2 ⊦ ((σ to n) + ⌜x⌝ )[(n1 + n) + n0] = x[n1 + n0], x = [], # σ < ⌜n⌝

Proof step 43 from proof from-append-add (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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