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Proof step 10 from proof from-cons-one (previous step)

⊦ ⌜λ n. (n = 0 ⊃ a;nf(n -1))⌝ from 1 = ⌜nf⌝

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
⊦ (λ n. (n = 0 ⊃ a;nf(n - 1))) from 1 = nf

Rule argument

Additional information

Used simplifier rules: from-inf: ⊦ ⌜nf⌝ from n = ⌜nf from n⌝ ;% ⊦ ⌜nf⌝ = ⌜nf0⌝ ↔ nf = nf0; (s)% ⊦ n -1 = n - 1; (s)