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Proof step 10 from proof from-from (previous step)

⊦ ⌜nf⌝ from m from n = ⌜nf⌝ from m + n, # ⌜nf⌝ < ⌜m⌝ + ⌜n⌝

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
⊦ nf from m from n = nf from m + n

Rule argument

Additional information

Used simplifier rules: from-inf: ⊦ ⌜nf⌝ from n = ⌜nf from n⌝ ;%size-inf: ⊦ # ⌜nf⌝ = ∞;% ⊦ ¬ ∞ < n∞; (s)% ⊦ ⌜nf⌝ = ⌜nf0⌝ ↔ nf = nf0; (s)