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Proof step 3 from proof get-finto (previous step)

m < n, m < # x, n ≤ # x ⊦ (x to n)[m] = x[m], x = []

User applied rule structural induction

And obtained the following new goals

Proof step 4:
m < #(a + x0), m < n, n ≤ #(a + x0), ∀ m, n. m < n ∧ m < # x0 ∧ n ≤ # x0 → (x0 to n)[m] = x0[m] ∨ x0 = [] ⊦ a + x0 = [], (a + x0 to n)[m] = (a + x0)[m]

Rule argument

indvar: x

Additional information

Used simplifier rules: list freely generated by [], +;;