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Proof step 2 from proof leq-symm-2 (
previous step
)
σ1 ≤ σ2 ⊦ σ2 ≤ σ1 ↔ σ1 = σ2
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 3
:
σ1 ≤ σ2, σ2 ≤ σ1 ⊦ σ1 = σ2
Rule argument
Additional information