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Proof step 5 from proof leq-symm-2 (previous step)

σ2 ≤ σ1, ∃ σ. σ1 + σ = σ2 ⊦ σ1 = σ2

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
⌜x⌝ + σ ≤ ⌜x⌝ ⊦ σ = []

Rule argument

Additional information

Used simplifier rules: append-cancel-l-02: ⊦ σ0 + σ = σ0 ↔ σ = [] ∨ ¬ finp(σ0);%append-assoc: ⊦ (σ + σ1) + σ2 = σ + σ1 + σ2;% ⊦ finp(⌜x⌝ ); (s)%stream-fin-forward: ⊦ finp(σ) → (∃ x. ⌜x⌝ = σ); (forward) from specification stream-basic