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Proof step 1 from proof neq-fin-inf-03 (conclusion)

⊦ σ0 + ⌜x⌝ = ⌜nf0⌝ ↔ σ0 = ⌜nf0⌝

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
σ0 + ⌜x⌝ = ⌜nf0⌝ ⊦ σ0 = ⌜nf0⌝

Rule argument

Additional information

Used simplifier rules: append-inf: ⊦ ⌜nf⌝ + σ = ⌜nf⌝ ;%append-assoc: ⊦ (σ + σ1) + σ2 = σ + σ1 + σ2;% ⊦ ⌜nf⌝ = ⌜nf0⌝ ↔ nf = nf0; (s)