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Proof step 4 from proof to-from-01 (previous step)

n < # x ⊦ (x to n) from n = [], x = []

User applied rule structural induction

And obtained the following new goals

Proof step 5:
n < #(a + x0), ∀ n. n < # x0 → (x0 to n) from n = [] ∨ x0 = [] ⊦ a + x0 = [], (a + x0 to n) from n = []

Rule argument

indvar: x

Additional information

Used simplifier rules: list freely generated by [], +;;