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Proof step 24 from proof to-to-leq (previous step)

n0 < # x, ∀ m, x. m ≤ n0 ∧ n0 ≤ # x ∧ m ≤ # x → x to n0 to m = x to m ⊦ x to n0 to n0 = x to n0, x = []

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 2 terms: n0, x

Additional information

Used simplifier rules: ⊦ m ≤ m; (s)% ⊦ m < n → m ≤ n; (s) Used terms: n0, x