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Proof step 14 from proof to-unwind-end (previous step)

⊦ ⌜a '⌝ + ⌜nf⌝ = [], (nf to m) + nf(m) ' = nf to m + 1

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 15:
⊦ ⌜a '⌝ + ⌜nf⌝ = ⌜λ n. (n = 0 ⊃ a;nf(n -1))⌝
Proof step 16:
⊦ (nf to m) + nf(m) ' = nf to m + 1, ⌜λ n. (n = 0 ⊃ a;nf(n -1))⌝ = []

Rule argument

spec: <toplevel> name: one-inf seq: ⊦ ⌜a '⌝ + ⌜nf⌝ = ⌜λ n. (n = 0 ⊃ a;nf(n -1))⌝ subst: [nf, a] → [nf, a] flags: <all paths>

Additional information

Used terms: nf, a